Foot-pound per Second to Kilocalorie per Hour (thermochemical) Converter
Power · unit-converter
Convert Foot-pound per Second to Kilocalorie per Hour (thermochemical) with a fixed input and output unit, step-by-step formula line, and reference tables. Linear units use SI watt definitions; mechanical hp uses 550 ft·lbf/s; BTU/h uses the IT BTU; dBm/dBW are logarithmic relative to 1 mW and 1 W. The full Power Converter also includes PS/CV, TR, kVA/MVA, and ft·lb/s.
Calculator
From: Foot-pound per Second (ft_lb_s)
To: Kilocalorie per Hour (thermochemical) (kcal_h)
About Foot-pound per Second
Foot-pounds per second is a mechanical power rate: 1 ft·lb/s = 1.3558179483314004 W (exactly, from the international foot definition).
About Kilocalorie per Hour (thermochemical)
Kilocalories per hour is a thermal power rate using the thermochemical kilocalorie (4,184 J per kcal) spread over one hour.
How to convert foot-pounds per second to kilocalories per hour (thermochemical)
1 foot-pound per second is equal to 1.16657376051459 kilocalorie per hour (thermochemical) when both are expressed in watt-equivalents:
1 ft_lb_s = (1.3558179483314003 W ÷ 1.1622222222222223 W) kcal_h = 1.16657376051459 kcal_h
Each foot-pound per second is defined as 1.3558179483314003 W and each kilocalorie per hour (thermochemical) as 1.1622222222222223 W in this tool, so one ft_lb_s equals 1.3558179483314003 ÷ 1.1622222222222223 kcal_h = 1.16657376051459 kcal_h.
Let d(ft_lb_s) be the numeric value in Foot-pound per Second (ft_lb_s), and d(kcal_h) the value in Kilocalorie per Hour (thermochemical) (kcal_h). Then:
d(kcal_h) = d(ft_lb_s) × (1.3558179483314003 / 1.1622222222222223)
Equivalently, divide by how many ft_lb_s fit into one kcal_h (watts per kcal_h divided by watts per ft_lb_s):
d(kcal_h) = d(ft_lb_s) ÷ 0.85721112016002
Or: kilocalorie per hour (thermochemical) = foot-pound per second ÷ 0.85721112016002
Examples
Example #1: Convert 1 ft_lb_s to kilocalorie per hour (thermochemical)
1 ft_lb_s = 1 ft_lb_s × (1.3558179483314003/1.1622222222222223) kcal_h = 1.1665737605 kcal_h
1 ft_lb_s = 1 ft_lb_s ÷ 0.85721112016002 = 1.1665737605 kcal_h
Intermediate watts: 1.3558179483 W
Example #2: Convert 10 ft_lb_s to kilocalorie per hour (thermochemical)
10 ft_lb_s = 10 ft_lb_s × (1.3558179483314003/1.1622222222222223) kcal_h = 11.6657376051 kcal_h
10 ft_lb_s = 10 ft_lb_s ÷ 0.85721112016002 = 11.6657376051 kcal_h
Intermediate watts: 13.5581794833 W
Summary
To convert Foot-pound per Second to Kilocalorie per Hour (thermochemical), multiply the value in ft_lb_s by the ratio of watts per ft_lb_s divided by watts per kcal_h. Equivalently: value_kcal_h = value_ft_lb_s × (1.3558179483314003 / 1.1622222222222223). Numerically, 1 ft_lb_s equals 1.1665737605145892 kcal_h.
Relationship context
You are converting between mechanical power (horsepower, ft·lb/s) (Foot-pounds per Second) and thermal engineering rates (BTU/h, kcal/h) (Kilocalories per Hour (thermochemical)). All linear values are mapped through watts first. The numeric factor is 1.166574e+0.
Conversion tables
| Foot-pound per Second (ft_lb_s) | Kilocalorie per Hour (thermochemical) (kcal_h) |
|---|---|
| 0.1 | 0.1166573761 |
| 1 | 1.1665737605 |
| 2 | 2.333147521 |
| 3 | 3.4997212815 |
| 4 | 4.6662950421 |
| 5 | 5.8328688026 |
| 6 | 6.9994425631 |
| 7 | 8.1660163236 |
| 8 | 9.3325900841 |
| 9 | 10.4991638446 |
| Foot-pound per Second (ft_lb_s) | Kilocalorie per Hour (thermochemical) (kcal_h) |
|---|---|
| 10 | 11.6657376051 |
| 20 | 23.3314752103 |
| 30 | 34.9972128154 |
| 40 | 46.6629504206 |
| 50 | 58.3286880257 |
| 60 | 69.9944256309 |
| 70 | 81.660163236 |
| 80 | 93.3259008412 |
| 90 | 104.991638446 |
| 100 | 116.657376051 |