Kilocalorie per Hour (thermochemical) to Megavolt-Ampere (MVA) Converter
Power · unit-converter
Convert Kilocalorie per Hour (thermochemical) to Megavolt-Ampere (MVA) with a fixed input and output unit, step-by-step formula line, and reference tables. Linear units use SI watt definitions; mechanical hp uses 550 ft·lbf/s; BTU/h uses the IT BTU; dBm/dBW are logarithmic relative to 1 mW and 1 W. The full Power Converter also includes PS/CV, TR, kVA/MVA, and ft·lb/s.
Calculator
From: Kilocalorie per Hour (thermochemical) (kcal_h)
To: Megavolt-Ampere (MVA) (mva)
About Kilocalorie per Hour (thermochemical)
Kilocalories per hour is a thermal power rate using the thermochemical kilocalorie (4,184 J per kcal) spread over one hour.
About Megavolt-Ampere (MVA)
One megavolt-ampere equals 1,000,000 VA. Common in transformer and grid-scale apparent-power ratings.
How to convert kilocalories per hour (thermochemical) to megavolt-amperes (mva, unity pf)
1 kilocalorie per hour (thermochemical) is equal to 0.00000116222222 megavolt-ampere (mva) when both are expressed in watt-equivalents:
1 kcal_h = (1.1622222222222223 W ÷ 1,000,000 W) mva = 0.00000116222222 mva
Each kilocalorie per hour (thermochemical) is defined as 1.1622222222222223 W and each megavolt-ampere (mva) as 1,000,000 W in this tool, so one kcal_h equals 1.1622222222222223 ÷ 1,000,000 mva = 0.00000116222222 mva.
Let d(kcal_h) be the numeric value in Kilocalorie per Hour (thermochemical) (kcal_h), and d(mva) the value in Megavolt-Ampere (MVA) (mva). Then:
d(mva) = d(kcal_h) × (1.1622222222222223 / 1,000,000)
Equivalently, divide by how many kcal_h fit into one mva (watts per mva divided by watts per kcal_h):
d(mva) = d(kcal_h) ÷ 860420.65009560226463
Or: megavolt-ampere (mva) = kilocalorie per hour (thermochemical) ÷ 860420.65009560226463
Examples
Example #1: Convert 1 kcal_h to megavolt-ampere (mva)
1 kcal_h = 1 kcal_h × (1.1622222222222223/1,000,000) mva = 0.0000011622 mva
1 kcal_h = 1 kcal_h ÷ 860420.65009560226463 = 0.0000011622 mva
Intermediate watts: 1.1622222222 W
Example #2: Convert 10 kcal_h to megavolt-ampere (mva)
10 kcal_h = 10 kcal_h × (1.1622222222222223/1,000,000) mva = 0.0000116222 mva
10 kcal_h = 10 kcal_h ÷ 860420.65009560226463 = 0.0000116222 mva
Intermediate watts: 11.6222222222 W
Summary
To convert Kilocalorie per Hour (thermochemical) to Megavolt-Ampere (MVA), multiply the value in kcal_h by the ratio of watts per kcal_h divided by watts per mva. Equivalently: value_mva = value_kcal_h × (1.1622222222222223 / 1000000). Numerically, 1 kcal_h equals 0.0000011622222222222223 mva.
Relationship context
You are converting between thermal engineering rates (BTU/h, kcal/h) (Kilocalories per Hour (thermochemical)) and apparent power at unity PF (VA) (Megavolt-Amperes (MVA, unity PF)). All linear values are mapped through watts first. The numeric factor is 1.162222e-6.
Conversion tables
| Kilocalorie per Hour (thermochemical) (kcal_h) | Megavolt-Ampere (MVA) (mva) |
|---|---|
| 0.1 | 0.0000001162 |
| 1 | 0.0000011622 |
| 2 | 0.0000023244 |
| 3 | 0.0000034867 |
| 4 | 0.0000046489 |
| 5 | 0.0000058111 |
| 6 | 0.0000069733 |
| 7 | 0.0000081356 |
| 8 | 0.0000092978 |
| 9 | 0.00001046 |
| Kilocalorie per Hour (thermochemical) (kcal_h) | Megavolt-Ampere (MVA) (mva) |
|---|---|
| 10 | 0.0000116222 |
| 20 | 0.0000232444 |
| 30 | 0.0000348667 |
| 40 | 0.0000464889 |
| 50 | 0.0000581111 |
| 60 | 0.0000697333 |
| 70 | 0.0000813556 |
| 80 | 0.0000929778 |
| 90 | 0.0001046 |
| 100 | 0.0001162222 |